Frankyc2003
13-06-2013, 19:23
Evening everyone,
This thread is a bit of a brain dump, so please bear with me. I wanted to share a quick set of (soft) rules that helped me determining the correct loading of my cartridge. So here we go, and please let me know if I made any mistakes, if I have forgotten anything, or if you feel something is just plain confusing...
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HOW TO DETERMINE THE OPTIMAL LOADING OF YOUR MC CARTRIDGE
Rule 1. A Step-up transformer of 1:10 ratio will have an internal impedance of 100 Ohm.
It's internal impedance is the square of it's step-up ratio.
1:5 ratio / 25 Ohm
1:10 ratio / 100 Ohm
1:20 ratio / 400 Ohm
.....................
Rule 2. The reflected impedance back to the cartridge you want to load is the impedance from the RIAA phono input divided by the internal impedance of the step-up transformer.
So for a 1:10 step-up plugged into a 47K Ohm phono, the reflected impedance would be 470 Ohm.
1:5 / 1880 Ohm
1:10 / 470 Ohm
1:20 / 117.5 Ohm
This is obviously without any form of loading on the secondary winding.
.......................
Rule 3. The average optimal loaded impedance for a cartridge is about 10 x it's internal impedance.
Lyra Clavis 2 Ohm / 20 Ohm
Denon Dl103R 14 Ohm / 140 Ohm
etc…
......................
Rule 4. To obtain the correct loaded impedance, you need to put a resistor in parallel on the secondary winding (output) or if you prefer in parallel with the input of the RIAA.
So the 2 resistors in parallel equation applies here.
(Product divided by sum)
R total = R1 x R2 / R1 + R2
So let's say I am using a 1:20 SUT with a Lyra Clavis. I will need to get the RIAA input impedance (or the secondary winding impedance) in the region of 8000 Ohm. You will get to this resistance value of around 8000 Ohm by adding a 10K resistor across the output of the SUT (secondary winding).
47000 x 10000 / 47000 + 10000 = 8245 Ohm
Then we see that by adding this 10K resistor we have achieved near enough optimal loading of our cartridge.
8245 / 400 = 20.61 Ohm (following rule 2.)
This gives you an easy way to determine the best resistor to use in your system.
++++++++++++++++++++++++++++++++++++++++++++++++++
This thread is a bit of a brain dump, so please bear with me. I wanted to share a quick set of (soft) rules that helped me determining the correct loading of my cartridge. So here we go, and please let me know if I made any mistakes, if I have forgotten anything, or if you feel something is just plain confusing...
------------------------------------------------------------------------------------
HOW TO DETERMINE THE OPTIMAL LOADING OF YOUR MC CARTRIDGE
Rule 1. A Step-up transformer of 1:10 ratio will have an internal impedance of 100 Ohm.
It's internal impedance is the square of it's step-up ratio.
1:5 ratio / 25 Ohm
1:10 ratio / 100 Ohm
1:20 ratio / 400 Ohm
.....................
Rule 2. The reflected impedance back to the cartridge you want to load is the impedance from the RIAA phono input divided by the internal impedance of the step-up transformer.
So for a 1:10 step-up plugged into a 47K Ohm phono, the reflected impedance would be 470 Ohm.
1:5 / 1880 Ohm
1:10 / 470 Ohm
1:20 / 117.5 Ohm
This is obviously without any form of loading on the secondary winding.
.......................
Rule 3. The average optimal loaded impedance for a cartridge is about 10 x it's internal impedance.
Lyra Clavis 2 Ohm / 20 Ohm
Denon Dl103R 14 Ohm / 140 Ohm
etc…
......................
Rule 4. To obtain the correct loaded impedance, you need to put a resistor in parallel on the secondary winding (output) or if you prefer in parallel with the input of the RIAA.
So the 2 resistors in parallel equation applies here.
(Product divided by sum)
R total = R1 x R2 / R1 + R2
So let's say I am using a 1:20 SUT with a Lyra Clavis. I will need to get the RIAA input impedance (or the secondary winding impedance) in the region of 8000 Ohm. You will get to this resistance value of around 8000 Ohm by adding a 10K resistor across the output of the SUT (secondary winding).
47000 x 10000 / 47000 + 10000 = 8245 Ohm
Then we see that by adding this 10K resistor we have achieved near enough optimal loading of our cartridge.
8245 / 400 = 20.61 Ohm (following rule 2.)
This gives you an easy way to determine the best resistor to use in your system.
++++++++++++++++++++++++++++++++++++++++++++++++++